Question

 3• sin 60º • tg 45º • ctg 60º​

Answer 1

Ответ:

Пошаговое объяснение:

Answer 2

To calculate the value of the expression $3 \cdot \sin(60^\circ) \cdot \tan(45^\circ) \cdot \cot(60^\circ)$, you can follow these steps:

1. Find the values of the trigonometric functions for the given angles:

   • $\sin(60^\circ)$ is $\sqrt{3}/2$.
   • $\tan(45^\circ)$ is 1.
   • $\cot(60^\circ)$ is $1/\tan(60^\circ)$.

2. Calculate $\tan(60^\circ)$:

   • $\tan(60^\circ) = \sqrt{3}$.

3. Now, calculate $\cot(60^\circ)$:

   • $\cot(60^\circ) = 1/\tan(60^\circ) = 1/\sqrt{3} = \sqrt{3}/3$.

4. Now, you can substitute these values into the expression and calculate it: $3 \cdot \left(\frac{\sqrt{3}}{2}\right) \cdot 1 \cdot \left(\frac{\sqrt{3}}{3}\right) = \frac{3 \cdot \sqrt{3} \cdot 1 \cdot \sqrt{3}}{2 \cdot 3} = \frac{9}{6} = \frac{3}{2}.$

So, $3 \cdot \sin(60^\circ) \cdot \tan(45^\circ) \cdot \cot(60^\circ) = \frac{3}{2}$.