Question

(7-2/3):(1 3/4-1/6)*(1 1/5+2 2/3+ 1/6)=​

Answer 1

Ответ:

16 2/15

Пошаговое объяснение:

(7-2/3):(1 3/4-1/6)*(1 1/5+2 2/3+1/6)

1)7-2/3=6 3/3-2/3=6 1/3

2)1 3/4-1/6=1 9/12-2/12=1 7/12

3)1 1/5+2 2/3=1 3/15+2 10/15=3 13/15

4)3 13/15+1/6=3 26/30+5/30=3 31/30=4 1/30

5)6 1/3:1 7/12=19/3:19/12=19/3*12/19=1/1*4/1=1*4=4

6)4*4 1/30=4*121/30=484/30=16 4/30=16 2/15

Answer 2

To solve this expression, follow these steps:

Step 1: Simplify the fractions in the expression.

First, convert all mixed numbers into improper fractions.

7 - 2/3 = 21/3 - 2/3 = 19/3

1 3/4 = 4/4 + 3/4 = 7/4

1 1/5 = 5/5 + 1/5 = 6/5

2 2/3 = 3 * 2 + 2/3 = 8/3

Step 2: Perform the operations within the parentheses.

(19/3) / ((7/4 - 1/6) * (6/5 + 8/3 + 1/6))

Step 3: Continue simplifying within the parentheses.

7/4 - 1/6 = (7/4 * 3/3) - (1/6 * 2/2) = 21/12 - 2/12 = 19/12

6/5 + 8/3 + 1/6 = (6/5 * 12/12) + (8/3 * 4/4) + (1/6 * 2/2) = 72/60 + 32/12 + 2/12 = (72 + 160 + 2) / 60 = 234/60

Step 4: Rewrite the expression with the simplified fractions.

(19/3) / ((19/12) * (234/60))

Step 5: Invert the second fraction and multiply.

(19/3) * (60/234)

Step 6: Simplify the multiplication.

(19/3) * (10/39)

Step 7: Multiply the numerators and denominators.

(19 * 10) / (3 * 39) = 190 / 117

Step 8: Simplify the fraction.

190/117 cannot be simplified further, so that's your final answer.

So, (7 - 2/3) / (1 3/4 - 1/6) * (1 1/5 + 2 2/3 + 1/6) = 190/117.