Question

1. 5x-2(3x+2)= x+20 2. -5(x-3)= 153. 4x(3x+1)- 3x(4x-1)= 144. 8(7-4x)= 7(4x+1), 5(8x-1)+24​

Answer 1

1) 5х-6х-х=20+4

-2х=24

х=-12

2)-5х=15-15

х=0

3)12х(квадрат)+4х-12х(квадрат)+3х=14

7х=14

х=2

4)-32х-28х=7-56

-60х=-49

х=49/60

-32х-40х=24-5-56

-72х=-37

х=37/72

Answer 2

Let's solve each equation step by step:

1. $5x - 2(3x + 2) = x + 20$

First, distribute the -2 on the left side of the equation:

$5x - 6x - 4 = x + 20$

Now, combine like terms on both sides of the equation:

$-x - 4 = x + 20$

Add x to both sides of the equation to isolate the variable:

$-4 = 2x + 20$

Subtract 20 from both sides:

$-4 - 20 = 2x$

$-24 = 2x$

Now, divide both sides by 2 to solve for x:

$-24 / 2 = 2x / 2$

$-12 = x$

So, the solution to the first equation is $x = -12$.

2. $-5(x - 3) = 15$

First, distribute the -5 on the left side of the equation:

$-5x + 15 = 15$

Now, subtract 15 from both sides to isolate the variable:

$-5x + 15 - 15 = 15 - 15$

$-5x = 0$

Now, divide both sides by -5 to solve for x:

$-5x / -5 = 0 / -5$

$x = 0$

So, the solution to the second equation is $x = 0$.

3. $4x(3x + 1) - 3x(4x - 1) = 14$

First, distribute and simplify both sides of the equation:

$12x^2 + 4x - 12x^2 + 3x = 14$

Now, combine like terms:

$4x - 3x = 14$

$x = 14$

So, the solution to the third equation is $x = 14$.

4. $8(7 - 4x) = 7(4x + 1)$

First, distribute and simplify both sides of the equation:

$56 - 32x = 28x + 7$

Now, add 32x to both sides to isolate the variable:

$56 - 32x + 32x = 28x + 32x + 7$

$56 = 56x + 7$

Subtract 7 from both sides:

$56 - 7 = 56x + 7 - 7$

$49 = 56x$

Now, divide both sides by 56 to solve for x:

$49 / 56 = 56x / 56$

$\frac{7}{8} = x$

So, the solution to the fourth equation is $x = \frac{7}{8}$.

5. $5(8x - 1) + 24 = 0$

First, distribute and simplify both sides of the equation:

$40x - 5 + 24 = 0$

Now, combine like terms:

$40x + 19 = 0$

Subtract 19 from both sides:

$40x + 19 - 19 = 0 - 19$

$40x = -19$

Now, divide both sides by 40 to solve for x:

$40x / 40 = -19 / 40$

$x = -\frac{19}{40}$

So, the solution to the fifth equation is $x = -\frac{19}{40}$.