Question

5/6х,+3=1/6х3(х+6)=2(х-3)​

Answer 1

Ответ:

Пошаговое объяснение:

5/6х+3=1/6х

4/6х= -3

х= -3:6/4

х= - 1/2

3(х+6)=2(х-3)​

3х+18=2х-6

х= - 24

Answer 2

It looks like you've written two equations:

1. $\frac{5}{6}x + 3 = \frac{1}{6}x$
2. $3(x+6) = 2(x-3)$

Let's solve these equations one by one:

Equation 1:

$\frac{5}{6}x + 3 = \frac{1}{6}x$

To solve this equation, you want to get all the terms involving x on one side and constants on the other side.

First, let's move the $\frac{5}{6}x$ term to the right side by subtracting $\frac{5}{6}x$ from both sides of the equation:

$3 = \frac{1}{6}x - \frac{5}{6}x$

Now, combine the x terms on the right side:

$3 = -\frac{4}{6}x$

Simplify the fraction:

$3 = -\frac{2}{3}x$

Now, to isolate x, you can multiply both sides of the equation by $-\frac{3}{2}$ (which is the same as dividing by $-\frac{2}{3}$):

$x = 3 \cdot -\frac{3}{2}$

$x = -\frac{9}{2}$

Equation 2:

$3(x+6) = 2(x-3)$

Let's distribute the constants on the left side:

$3x + 18 = 2x - 6$

Now, move all the terms involving x to the left side by subtracting 2x from both sides:

$3x - 2x + 18 = -6$

Simplify the left side:

$x + 18 = -6$

Now, isolate x by subtracting 18 from both sides:

$x = -6 - 18$

$x = -24$

So, the solutions to the equations are:

1. $x = -\frac{9}{2}$
2. $x = -24$