Question

(2x+1)(x-3)=x(4-x)-9 Plz

Answer 1

2х^2-6х+х-3=4х-х^2-9
2х^2-5х-3=4х-х^2-9
2х^2-5х-3-4х+х^2+9=0
3х^2-9х+6=0 |:3
х^2-3х+2=0
х1=1 х2=2
(по теор. Виета)

Answer 2

To solve the equation (2x+1)(x-3) = x(4-x) - 9, follow these steps:

1. Expand both sides of the equation:

   (2x+1)(x-3) = x(4-x) - 9

   2x(x) + 2x(-3) + 1(x) + 1(-3) = 4x - x^2 - 9

2. Simplify each term on both sides:

   2x^2 - 6x + x - 3 = 4x - x^2 - 9

3. Combine like terms:

   2x^2 - 5x - 3 = 4x - x^2 - 9

4. Move all terms to one side of the equation to set it equal to zero:

   2x^2 - 5x - 3 - 4x + x^2 + 9 = 0

5. Combine like terms again:

   2x^2 + x^2 - 5x - 4x - 3 + 9 = 0

   3x^2 - 9x + 6 = 0

6. Divide the entire equation by 3 to simplify it:

   x^2 - 3x + 2 = 0

7. Now, you can solve this quadratic equation by factoring:

   (x - 2)(x - 1) = 0

8. Set each factor equal to zero and solve for x:

   x - 2 = 0 --> x = 2 x - 1 = 0 --> x = 1

So, the solutions to the equation (2x+1)(x-3) = x(4-x) - 9 are x = 2 and x = 1.