Question

1-sin^2(270°+a) 1-cos^2(270°-a) 1-sin^2(360°-a) 1-cos^2(360°+a) 1+ctg^2(270°-a) 1+ctg^2(360°-a)

Answer 1

Ответ:

решение на фотографии

Answer 2

Let's simplify each of the given trigonometric expressions step by step:

1. 1 - sin^2(270° + a): We know that sin(270° + a) = -cos(a), so: 1 - sin^2(270° + a) = 1 - (-cos(a))^2 = 1 - cos^2(a)

2. 1 - cos^2(270° - a): We know that cos(270° - a) = sin(a), so: 1 - cos^2(270° - a) = 1 - sin^2(a)

3. 1 - sin^2(360° - a): We know that sin(360° - a) = sin(a), so: 1 - sin^2(360° - a) = 1 - sin^2(a)

4. 1 - cos^2(360° + a): We know that cos(360° + a) = cos(a), so: 1 - cos^2(360° + a) = 1 - cos^2(a)

5. 1 + cot^2(270° - a): We know that cot(270° - a) = -tan(a), so: 1 + cot^2(270° - a) = 1 + (-tan(a))^2 = 1 + tan^2(a)

6. 1 + cot^2(360° - a): We know that cot(360° - a) = cot(a), so: 1 + cot^2(360° - a) = 1 + cot^2(a)

So, in summary:

1. 1 - sin^2(270° + a) = 1 - cos^2(a)
2. 1 - cos^2(270° - a) = 1 - sin^2(a)
3. 1 - sin^2(360° - a) = 1 - sin^2(a)
4. 1 - cos^2(360° + a) = 1 - cos^2(a)
5. 1 + cot^2(270° - a) = 1 + tan^2(a)
6. 1 + cot^2(360° - a) = 1 + cot^2(a)