Question

1)3х-7<х+1 2)2+х>8-х​

Answer 1

Ответ:

Пошаговое объяснение:

1) 3x-x<1+7

2x<8

x<4

2) x+x>8-2

2x>6

x>3

Answer 2

Let's solve these two inequalities step by step:

1. $3x - 7 < x + 1$

First, let's get all the x terms on one side of the inequality and the constants on the other side:

Subtract $x$ from both sides:

$3x - x - 7 < 1$

This simplifies to:

$2x - 7 < 1$

Now, add 7 to both sides:

$2x - 7 + 7 < 1 + 7$

$2x < 8$

Finally, divide both sides by 2:

$x < 4$

So, the solution to the first inequality is $x < 4$.

2. $2 + x > 8 - x$

First, let's get all the x terms on one side of the inequality and the constants on the other side:

Add $x$ to both sides:

$2 + x + x > 8$

This simplifies to:

$2 + 2x > 8$

Now, subtract 2 from both sides:

$2 + 2x - 2 > 8 - 2$

$2x > 6$

Finally, divide both sides by 2:

$2x / 2 > 6 / 2$

$x > 3$

So, the solution to the second inequality is $x > 3$.

To summarize:

1. $x < 4$
2. $x > 3$