
3) |x|+6=1 4) |x|+12=8


Ответы на вопрос

Ответ:
х+12=8
х=12-8
х=-4
-4+12=8
Пошаговое объяснение:
12-х=8
х=12-8
х=4
12-4=8
8=8



To solve the equations |x| + 6 = 1 and |x| + 12 = 8, you'll need to consider two cases for each equation: one where x is positive, and another where x is negative.
Let's start with the first equation:
- |x| + 6 = 1
Case 1: x is positive (x > 0) For x > 0, |x| is just x. So the equation becomes: x + 6 = 1
Now, subtract 6 from both sides of the equation: x = 1 - 6 x = -5
Case 2: x is negative (x < 0) For x < 0, |x| is -x. So the equation becomes: -x + 6 = 1
Now, subtract 6 from both sides of the equation: -x = 1 - 6 -x = -5
To isolate x, multiply both sides by -1 (since -x is the same as multiplying x by -1):
x = 5
So for the first equation |x| + 6 = 1, you have two solutions: x = -5 and x = 5.
Now, let's move on to the second equation:
- |x| + 12 = 8
Case 1: x is positive (x > 0) For x > 0, |x| is just x. So the equation becomes: x + 12 = 8
Now, subtract 12 from both sides of the equation: x = 8 - 12 x = -4
Case 2: x is negative (x < 0) For x < 0, |x| is -x. So the equation becomes: -x + 12 = 8
Now, subtract 12 from both sides of the equation: -x = 8 - 12 -x = -4
To isolate x, multiply both sides by -1 (since -x is the same as multiplying x by -1):
x = 4
So for the second equation |x| + 12 = 8, you have two solutions: x = -4 and x = 4.


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