Question

Ctg(270°-a)•tg(90°+a)​

Answer 1

Ответ:все в картинке если не сложно сделай ответ лучшим)

Пошаговое объяснение:

Answer 2

Ответ: -1

Пошаговое объяснение:

В прикреплённом файле

Answer 3

To simplify the expression $\cot(270^\circ - a) \cdot \tan(90^\circ + a)$, you can use trigonometric identities and properties.

1. Recall that $\cot(\theta)$ is the reciprocal of $\tan(\theta)$, which means $\cot(\theta) = \frac{1}{\tan(\theta)}$.

2. Also, remember that $\tan(90^\circ + \alpha)$ is undefined because the tangent function is undefined at odd multiples of 90 degrees (e.g., $\tan(90^\circ)$, $\tan(270^\circ)$, etc.).

Given these facts, let's simplify the expression:

$\cot(270^\circ - a) \cdot \tan(90^\circ + a)$

First, let's find the value of $\cot(270^\circ - a)$:

$\cot(270^\circ - a) = \frac{1}{\tan(270^\circ - a)}$

Now, we know that $\tan(270^\circ - a) = -\tan(a)$ because the tangent function has a period of 180 degrees, and $\tan(270^\circ) = -\tan(90^\circ) = -\infty$. So:

$\cot(270^\circ - a) = \frac{1}{-\tan(a)} = -\frac{1}{\tan(a)}$

Now, we have:

$-\frac{1}{\tan(a)} \cdot \tan(90^\circ + a)$

As mentioned earlier, $\tan(90^\circ + a)$ is undefined, so the final result is undefined as well:

$-\frac{1}{\tan(a)} \cdot \text{undefined} = \text{undefined}$

Therefore, the expression $\cot(270^\circ - a) \cdot \tan(90^\circ + a)$ is undefined.