Question

X+2y+z=8 2x+y+z=8 3x+2y-2z=4

Answer 1

Ответ:

будет

х+9-х3

х-8+6х

х+4+6+х

х-0

Пошаговое объяснение:

Answer 2

Ововлу/77282!2?(26/)?2(2627)2)2)

Answer 3

You have a system of three linear equations with three variables:

1. x + 2y + z = 8
2. 2x + y + z = 8
3. 3x + 2y - 2z = 4

You can solve this system of equations using various methods, such as substitution, elimination, or matrix methods. I'll use the elimination method to solve this system:

First, let's subtract equation (1) from equation (2) to eliminate the variable z:

(2x + y + z) - (x + 2y + z) = 8 - 8 2x + y + z - x - 2y - z = 0

This simplifies to:

x - y = 0

Now, let's add equation (2) to equation (3) to eliminate the variable z again:

(2x + y + z) + (3x + 2y - 2z) = 8 + 4 2x + y + z + 3x + 2y - 2z = 12

Combine like terms:

5x + 3y = 12

Now, you have two equations:

1. x - y = 0
2. 5x + 3y = 12

You can solve this system of equations simultaneously. To do that, you can solve equation (1) for x:

x = y

Now, substitute this expression for x into equation (2):

5(y) + 3y = 12

6y = 12

Divide both sides by 6:

y = 2

Now that you have found the value of y, you can find the values of x and z using the equations:

x = y = 2 x = 2

Now, let's find z. You can use any of the original equations to do this. Let's use equation (1):

x + 2y + z = 8 2 + 2(2) + z = 8 2 + 4 + z = 8

Subtract 6 from both sides:

z = 8 - 6 z = 2

So, the solution to the system of equations is:

x = 2 y = 2 z = 2