Question

{ 10 – 4х > 3(1 – x), 3,5 + 0,25x < 2x

Answer 1

Ответ:

Внизу.

Пошаговое объяснение:

x ∈ ( 2;7)

Answer 2

To solve the inequalities $10 - 4x > 3(1 - x)$ and $3.5 + 0.25x < 2x$, we'll start with the first one:

$10 - 4x > 3(1 - x)$

Simplify both sides:

$10 - 4x > 3 - 3x$

Next, add $3x$ to both sides:

$10 - x > 3$

Subtract $10$ from both sides:

$-x > -7$

Since we're dividing by a negative number, we need to reverse the inequality sign:

$x < 7$

Now, let's move on to the second inequality:

$3.5 + 0.25x < 2x$

First, subtract $0.25x$ from both sides:

$3.5 < 1.75x$

Next, divide both sides by $1.75$:

$2 < x$

So, the solution to the system of inequalities is $x < 7$ and $x > 2$. These conditions can be combined as $2 < x < 7$.