Question

2(x -1) - 3(x+ 2) < 6(1+ x)​

Answer 1

Пошаговое объяснение:

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Answer 2

To solve the inequality $2(x - 1) - 3(x + 2) < 6(1 + x)$, you can follow these steps:

1. Distribute the constants on both sides of the inequality:

$2x - 2 - 3x - 6 < 6 + 6x$

2. Combine like terms on each side of the inequality:

$-x - 8 < 6 + 6x$

3. Add $x$ to both sides to isolate the $x$ terms on one side:

$-8 < 7x + 6$

4. Subtract 6 from both sides:

$-8 - 6 < 7x$

$-14 < 7x$

5. Divide both sides by 7 to solve for $x$:

$\frac{-14}{7} < x$

$-2 < x$

So, the solution to the inequality $2(x - 1) - 3(x + 2) < 6(1 + x)$ is $x > -2$.