Question

2. X+ y = 42x + 7y = 33. 3x - y = 23x + 2y = 5​

Answer 1

Ответ:

X+y=4

x+y-4=0

2x+7y=3

2x+7y-3=0

3x-y=2

3x-y-2=o

3x+2y=5

3x+2y-5=0

Answer 2

To solve this system of linear equations, you can use either the substitution method or the elimination method. Let's use the elimination method:

First, we'll write the equations in standard form:

1. x + y = 42
2. 33x + 7y = 33
3. 3x - y = 23
4. 23x + 2y = 5

Now, let's work with equations 1 and 2 to eliminate one of the variables. To do this, we can multiply equation 1 by 7 and equation 2 by -1 so that the coefficients of y in both equations cancel each other out:

7(x + y) = 7(42) -1(33x + 7y) = -1(33)

This simplifies to:

7x + 7y = 294 -33x - 7y = -33

Now, add these two equations together to eliminate y:

(7x + 7y) + (-33x - 7y) = 294 - 33

This results in:

(7x - 33x) = 261

-26x = 261

Now, divide both sides by -26 to solve for x:

x = -261 / 26 x = -10.0385 (approximately)

Now that we have the value of x, we can substitute it back into one of the original equations to solve for y. Let's use equation 1:

x + y = 42

-10.0385 + y = 42

Now, add 10.0385 to both sides:

y = 42 + 10.0385 y = 52.0385

So, the solution to the system of equations is:

x = -10.0385 y = 52.0385