Question

2x + 3 < x + 1;x - 5 > 3 - x;​

Answer 1

Пошаговое объяснение:

{2х+3<х+1

{х-5>3-х

{2х-х<1-3

{Х+Х>3+5

{Х< - 2

{2х>8

{Х< - 2

{Х>4

Ответ : нет решений

Answer 2

To solve the inequalities 2x + 3 < x + 1 and x - 5 > 3 - x, you can follow these steps:

1. Solve the first inequality, 2x + 3 < x + 1:

2x + 3 < x + 1

Subtract x from both sides:

2x - x + 3 < 1

x + 3 < 1

Subtract 3 from both sides:

x < 1 - 3

x < -2

So, the solution to the first inequality is x < -2.

2. Solve the second inequality, x - 5 > 3 - x:

x - 5 > 3 - x

Add x to both sides:

x + x - 5 > 3

2x - 5 > 3

Add 5 to both sides:

2x - 5 + 5 > 3 + 5

2x > 8

Now, divide both sides by 2:

2x/2 > 8/2

x > 4

So, the solution to the second inequality is x > 4.

Therefore, the combined solution to the system of inequalities is:

x < -2 and x > 4

This means there is no solution that satisfies both inequalities simultaneously since these inequalities have no overlapping solution.