Question

Re (12y + 18)(1,6 - 0,2y) = 0.​

Answer 1

Ответ:

X1=8 x2=-1,5

Пошаговое объяснение:

19.2y-2,4y²+28,8-3,6y=0

19,2y-3,6y-2,4y²+28,8=0

15,6y-2,4y²+28,8=0

a=-2,4 b=15,6 c=28,8

Д=b²-4ac=(15,6)²-4*(-2,4)*28,8=243,36+276,48=519,84=√519,84=22,8

x1;2=-b±√Д/2a=-15,6±22,8/2*(-2,4)= 1)-38,4/-4,8=8; 2)7,2/-4,8=-1,5

Answer 2

To solve the equation $(12y + 18)(1.6 - 0.2y) = 0$, we can follow these steps:

Expand the terms:

$(12y + 18)(1.6 - 0.2y) = 0$

$12y \times 1.6 - 12y \times 0.2y + 18 \times 1.6 - 18 \times 0.2y = 0$

$19.2y - 2.4y^2 + 28.8 - 3.6y = 0$

Simplify the equation:

$-2.4y^2 + 15.6y + 28.8 = 0$

Now we have a quadratic equation in the form $ax^2 + bx + c = 0$ where $a = -2.4$, $b = 15.6$, and $c = 28.8$. We can use the quadratic formula to solve for $y$:

$y = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}$

Plugging in the values:

$y = \frac{-15.6 \pm \sqrt{(15.6)^2 - 4(-2.4)(28.8)}}{2(-2.4)}$

$y = \frac{-15.6 \pm \sqrt{243.36 + 276.48}}{-4.8}$

$y = \frac{-15.6 \pm \sqrt{519.84}}{-4.8}$

$y = \frac{-15.6 \pm 22.8}{-4.8}$

Now we have two possible solutions:

1. $y = \frac{-15.6 + 22.8}{-4.8} = \frac{7.2}{-4.8} = -1.5$
2. $y = \frac{-15.6 - 22.8}{-4.8} = \frac{-38.4}{-4.8} = 8$

So the solutions for the equation are $y = -1.5$ and $y = 8$.