
4х - 6у = 2 3у - 2х = 1


Ответы на вопрос

Відповідь: Система розв'язків не має.
Розв'язання методом виключення змінної. В результаті (x;y) є ∅. ( 0 ≠ 4)




You have a system of two linear equations with two variables, x and y:
- 4x - 6y = 2
- 3y - 2x = 1
You can solve this system of equations using various methods, such as substitution or elimination. Here, I'll use the elimination method to solve the system:
Let's start by multiplying the second equation by 2 to make it easier to eliminate one of the variables:
- 4x - 6y = 2
- 6y - 4x = 2
Now, add the two equations together to eliminate the x variable:
(4x - 6y) + (6y - 4x) = 2 + 2
This simplifies to:
0 = 4
Since 0 does not equal 4, this system of equations is inconsistent and has no solution. In other words, the two lines represented by these equations are parallel and do not intersect, so there are no values of x and y that simultaneously satisfy both equations.



To solve the system of equations:
- 4x - 6y = 2
- 3y - 2x = 1
You can use the method of substitution or elimination. Let's use the elimination method. First, we can multiply the second equation by 2 to make it easier to eliminate one of the variables:
- 4x - 6y = 2
- 6y - 4x = 2
Now, add the two equations together to eliminate the x variable:
(4x - 6y) + (6y - 4x) = 2 + 2
This simplifies to:
0 = 4
This is not a possible equation, and it means that there is no solution to this system of equations. In other words, the two equations represent parallel lines that do not intersect in a common point.


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