Question

1) х - 5у - 3 = 0;2) 2x + 7y - 10 = 0;​

Answer 1

Ответ:

1)x-5y=3

2)2x+7y=10

Пошаговое объяснение:

1)

x-5y-3=0

x-5y=3

Единственное решение

2)

2x+7y-10=0

2x+7y=10

Здесь также

Answer 2

It seems like you've provided two linear equations:

1. $x - 5y - 3 = 0$
2. $2x + 7y - 10 = 0$

These are a system of two linear equations with two variables, $x$ and $y$. You can solve for the values of $x$ and $y$ by using different methods such as substitution or elimination. Let's use the elimination method to solve this system:

First, you can multiply the first equation by 2 to make the coefficients of $x$ in both equations equal:

1. $2x - 10y - 6 = 0$
2. $2x + 7y - 10 = 0$

Now, subtract the first equation from the second equation to eliminate $2x$:

$(2x + 7y - 10) - (2x - 10y - 6) = 0$

Simplifying:

$2x + 7y - 10 - 2x + 10y + 6 = 0$

This reduces to:

$17y - 4 = 0$

Now, add 4 to both sides:

$17y = 4$

Finally, divide both sides by 17 to solve for $y$:

$y = \frac{4}{17}$

Now that you have found the value of $y$, you can substitute it back into one of the original equations to find (x). Let's use the first equation:

$x - 5\left(\frac{4}{17}\right) - 3 = 0$

To solve for (x):

$x - \frac{20}{17} - 3 = 0$

Now, add $\frac{20}{17}$ and 3 to both sides:

$x = \frac{20}{17} + 3$

To add these fractions, you'll need a common denominator, which is 17:

$x = \frac{20}{17} + \frac{3 \cdot 17}{17} = \frac{20 + 51}{17} = \frac{71}{17}$

So, the solution to the system of equations is:

$x = \frac{71}{17}$ $y = \frac{4}{17}$