Question

(−5,1)⋅7 15/8⋅(2x−7,4)=0

Answer 1

Решение уравнения:

(-5,1)*7 15/8 * (2х-7,4)=0

2х-7,4=0

2х=7,4

х=3,7

Answer 2

To solve the equation $(-5,1) \cdot \frac{7}{15/8} \cdot (2x - 7,4) = 0$, we can simplify the expression and then solve for $x$.

Let's simplify the equation step by step:

1. Multiply $(-5,1)$ by $\frac{7}{15/8}$: $(-5,1) \cdot \frac{7}{15/8} = (-5,1) \cdot \frac{7}{1} \cdot \frac{8}{15} = (-5,1) \cdot \frac{56}{15}$

2. Now, we have $(-5,1) \cdot \frac{56}{15} \cdot (2x - 7,4) = 0$.

3. Multiply $(-5,1) \cdot \frac{56}{15}$: $(-5,1) \cdot \frac{56}{15} = (-5 \cdot \frac{56}{15}, 1 \cdot \frac{56}{15}) = (-\frac{280}{15}, \frac{56}{15}) = (-\frac{56}{3}, \frac{56}{15})$

4. Now, the equation becomes $(-56/3, 56/15) \cdot (2x - 7,4) = 0$.

5. Use the distributive property to expand the left side of the equation: $-\frac{56}{3} \cdot (2x - 7,4) + \frac{56}{15} \cdot (2x - 7,4) = 0$

6. Apply the distributive property again to each term: $-\frac{56}{3} \cdot 2x + \frac{56}{3} \cdot 7,4 + \frac{56}{15} \cdot 2x - \frac{56}{15} \cdot 7,4 = 0$

7. Simplify further: $-\frac{112}{3}x + \frac{208}{5}x - \frac{416}{15} - \frac{208}{3} = 0$

8. Combine like terms: $-\frac{112}{3}x + \frac{208}{5}x - \frac{416}{15} - \frac{208}{3} = 0$

9. Find a common denominator for the fractions in the equation. The common denominator is 15: $-\frac{560}{15}x + \frac{416}{15}x - \frac{832}{15} - \frac{208}{15} = 0$

10. Now, combine the terms with $x$: $-\frac{560x}{15} + \frac{416x}{15} - \frac{832}{15} - \frac{208}{15} = 0$