Question

Y = x - 5,4x + y = 10;3)(-x = 3 - 2y,[x - 5y = -6.​

Answer 1

Ответ:

у=х-5

4х+у=10

4х+х-5=10

5х=15

х=3

у=3-5 =-2

12+(-2)=10

-х=3-2у

х-5у=-6

х=-3+2у

-3+2у-5у=-6

-3у=-3

у-1

х-5=-6

х=-1

1=3-2

1=1

Пошаговое объяснение:

Answer 2

It seems like you have a system of linear equations, and you'd like to find the solution for the variables x and y in each of these systems. Let's solve each system one by one.

System 1:

1. $Y = x - 5$
2. $4x + y = 10$

We can solve this system using substitution or elimination. Let's use elimination:

From equation 1, we have $Y = x - 5$. We can substitute this into equation 2:

$4x + (x - 5) = 10$

Combine like terms:

$5x - 5 = 10$

Add 5 to both sides:

$5x = 15$

Now, divide by 5:

$x = 3$

Now that we have the value of x, we can find y using equation 1:

$Y = x - 5$ $Y = 3 - 5$ $Y = -2$

So, the solution to the first system is $x = 3$ and $y = -2$.

System 2:

1. $-x = 3 - 2y$
2. $x - 5y = -6$

Let's solve this system:

From equation 1, we have $-x = 3 - 2y$. We can multiply both sides by -1 to make it positive:

$x = -3 + 2y$

Now, we can substitute this into equation 2:

$(-3 + 2y) - 5y = -6$

Combine like terms:

$-3 - 3y = -6$

Add 3 to both sides:

$-3y = -3$

Now, divide by -3:

$y = 1$

Now that we have the value of y, we can find x using the equation we derived:

$x = -3 + 2y$ $x = -3 + 2(1)$ $x = -3 + 2$ $x = -1$

So, the solution to the second system is $x = -1$ and $y = 1$.