Question

{-х(1-12у)+4у(-3+2)=26

Answer 1

Ответ: у=2,5

Пошаговое объяснение:

-х(1-12у)+4у(-3х+2)=26

у(х+6)=х(у-3)-3

-х+12ху-12ху+8у=26

ху+6у=ху-3х-3

-х+12ху-12ху+8у=26

ху+6у-ху+3х=-3

-х+8у=26

6у+3х=-3

-х=26-8у | *(-1)

6у+3х=-3

х=-26+8у

6у+3х=-3

х=-26+8*2,5

х=-26+20

х=-6

6у+3(-26+8у)=-3

6у-78+24у=-3

30у-78=-3

30у=75

у=2,5

Answer 2

It seems you've provided an equation. To help you solve it, let's work through it step by step.

The equation you've given is: -х(1-12y) + 4y(-3+2) = 26

First, let's simplify the equation:

-х(1-12y) + 4y(-3+2) = 26

Now, distribute the negative sign in the first term and simplify further:

-x(1) + x(12y) + 4y(-1) = 26

Simplify the constants:

-x + 12xy - 4y = 26

Now, let's isolate the terms with 'x' on one side of the equation and move the constants to the other side:

• x + 12xy = 4y + 26

Now, factor out 'x' from the left side:

x(-1 + 12y) = 4y + 26

Now, divide both sides by (-1 + 12y) to solve for 'x':

x = (4y + 26) / (-1 + 12y)

So, the solution for 'x' in terms of 'y' is: x = (4y + 26) / (-1 + 12y)