Question

(x – 3y = -1(2x + y = 5​

Answer 1

Если это система то,
(x=3y-1
(2x-y=5
6y-2+y=5
7y=7
y=1

x=3-1
x=2

Answer 2

$x - 3y = - 1 \\ x - 3y + 1 = - 1 + 1 \\ x - 3y + 1 = 0$

$2x + y = 5 \\ 2x + y - 5 = 5 - 5 \\ 2x + y - 5 = 0$

Answer 3

To solve the system of equations:

1. x - 3y = -1
2. 2x + y = 5

You can use the method of substitution or elimination. I'll use the elimination method here.

First, let's multiply equation (1) by 2 to make it easier to eliminate one of the variables:

1. 2(x - 3y) = 2(-1) (Multiply equation 1 by 2) 2x - 6y = -2

Now you have the system of equations:

1. 2x - 6y = -2
2. 2x + y = 5

Now, you can subtract equation (2) from equation (1) to eliminate the variable x:

(2x - 6y) - (2x + y) = (-2) - 5

Now, simplify the equation:

2x - 6y - 2x - y = -7

-6y - y = -7

Combine like terms:

-7y = -7

Now, divide both sides by -7 to solve for y:

y = -7 / -7

y = 1

Now that you've found the value of y, you can substitute it back into either of the original equations to solve for x. Let's use equation (1):

x - 3(1) = -1

x - 3 = -1

Add 3 to both sides:

x = -1 + 3

x = 2

So, the solution to the system of equations is x = 2 and y = 1.