Question

17+с=24, 32-х=26, 7хУ=56

Answer 1

Ответ:

1. c=24-17

c= 7

2. x= 32-26

x= 6

3. y=56:7

y=8

Answer 2

Ответ:

1)17+с=24

с=24-17=7

2)32-х=26

х=32-26=6

3)7×у=56

56:7=8

Answer 3

To solve these equations for the variables, let's break them down one by one:

1. 17 + с = 24

   Subtract 17 from both sides to isolate с:

   с = 24 - 17 с = 7

2. 32 - х = 26

   Subtract 32 from both sides to isolate х:

   -х = 26 - 32 -х = -6

   Now, divide both sides by -1 to find the value of х:

   х = -6 / -1 х = 6

3. 7хУ = 56

   It seems like you've included an extra variable У in this equation. I'll assume you meant to write 7x = 56. If that's the case, you can solve it as follows:

   Divide both sides by 7 to isolate x:

   7x / 7 = 56 / 7 x = 8

So, the solutions are:

• с = 7
• х = 6