Question

22x²+22x+4x+4=144 оешиье уравнение​

Answer 1

Ответ:

22x^2+26x+4-144=0

22x^2+26x-140=0

11x^2+13x-70=0

11x^2+35x-22x-70=0

x(11x+35)-2(11x+35)=0

(11x+35)*(x-2)=0

11x+35=0

x-2=0

x= - 35/11

x=2

Ответ: x1 = - 35/11: x2=2

Пошаговое объяснение:

Answer 2

Let's solve this quadratic equation together! First, let's combine like terms:

$22x^2 + 22x + 4x + 4 = 144$

Combine the $x$ terms:

$22x^2 + 26x + 4 = 144$

Now, subtract 144 from both sides to set the equation to zero:

$22x^2 + 26x + 4 - 144 = 0$

Simplify further:

$22x^2 + 26x - 140 = 0$

Now, we can divide the entire equation by 2 to simplify it:

$11x^2 + 13x - 70 = 0$

Now, you can either factor this quadratic or use the quadratic formula. What would you like to do?