Question

F(x) =3/3x+2x, x0=1Срочнооооо! ​

Answer 1

Ответ:

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Answer 2

It seems like there might be a typographical error in your expression. Assuming you meant $f(x) = \frac{3}{3x} + 2x$, let's proceed.

First, simplify the expression:

$f(x) = \frac{3}{3x} + 2x$

Combine the terms with a common denominator:

$f(x) = \frac{3 + 6x^2}{3x}$

Now, if you want to find the value of $f(x)$ at $x_0 = 1$, substitute $x_0 = 1$ into the expression:

$f(1) = \frac{3 + 6(1)^2}{3(1)}$

Simplify further:

$f(1) = \frac{3 + 6}{3}$

$f(1) = \frac{9}{3}$

$f(1) = 3$

So, if $f(x) = \frac{3}{3x} + 2x$ and $x_0 = 1$, then $f(1) = 3$.