Question

На кольцевой дороге три города: A, B и C. Известно, что путь из А в С в 6 раз длиннее по дуге, не содержащей B, чем через В. Путь из В в С в 7 раз короче по дуге, не содержащей А, чем через А. Во сколько раз путь из А в B по дуге, не содержащей С, короче пути через С?​

Answer 1

Ответ:

ответ............... : 10

Пошаговое объяснение:

потому что

Answer 2

Problem Analysis

We are given a scenario where there are three cities, A, B, and C, located on a circular road. We are provided with two pieces of information: 1. The distance from A to C along a curve that does not pass through B is 6 times longer than the distance from A to B along a curve that does not pass through C. 2. The distance from B to C along a curve that does not pass through A is 7 times shorter than the distance from A to C along a curve that does not pass through B.

We need to determine the ratio of the distance from A to B along a curve that does not pass through C to the distance from A to C along a curve that does not pass through B.

Solution

Let's assume that the distance from A to C along a curve that does not pass through B is x. According to the given information, the distance from A to B along a curve that does not pass through C is x/6, and the distance from B to C along a curve that does not pass through A is x/7.

To find the ratio of the distance from A to B along a curve that does not pass through C to the distance from A to C along a curve that does not pass through B, we can set up the following equation:

(x/6) / (x/7) = (7x) / (6x) = 7/6

Therefore, the ratio of the distance from A to B along a curve that does not pass through C to the distance from A to C along a curve that does not pass through B is 7/6.

Answer

The ratio of the distance from A to B along a curve that does not pass through C to the distance from A to C along a curve that does not pass through B is 7/6.