Question

УМОЛЯЮ,ПОМОГИТЕ!!! ДАЮ 15 БАЛЛОВ Какое наибольшее количество нечётных цифр может быть в десятичной записи числа N, если его сумма цифр равна 200, а сумма цифр числа 5N равна 145?

Answer 1

Ответ:

29

Пошаговое объяснение:

Всё очень просто!!!

Answer 2

The maximum number of odd digits in the decimal representation of a number N, given that the sum of its digits is 200 and the sum of the digits of 5N is 145.

To find the maximum number of odd digits in the decimal representation of a number N, we need to consider the constraints provided: the sum of the digits of N is 200, and the sum of the digits of 5N is 145.

Let's break down the problem into smaller steps:

1. Determine the range of possible values for N: - Since the sum of the digits of N is 200, we know that N must be a three-digit number or larger. This is because the maximum sum of the digits of a two-digit number is 9 + 9 = 18. - To find the upper limit for N, we can assume that all the digits of N are 9. In this case, the sum of the digits would be 9 + 9 + 9 = 27. Since the sum of the digits of N is 200, the upper limit for N is 999.

2. Find the range of possible values for the sum of the digits of 5N: - To find the sum of the digits of 5N, we need to multiply each digit of N by 5 and sum them up. - Since the maximum value of N is 999, the maximum value of 5N is 4995. Therefore, the maximum sum of the digits of 5N is 4 + 9 + 9 + 5 = 27.

3. Determine the possible values for the sum of the digits of N that satisfy the constraints: - We know that the sum of the digits of N is 200, and the sum of the digits of 5N is 145. - By subtracting the sum of the digits of 5N from the sum of the digits of N, we can find the sum of the odd digits of N. - Let's denote the sum of the odd digits of N as O. Therefore, O = 200 - 145 = 55. - The sum of the even digits of N can be found by subtracting O from the sum of the digits of N: E = 200 - 55 = 145. - Since the sum of the even digits of N is 145, and each even digit can be either 0, 2, 4, 6, or 8, we can conclude that there are no odd digits in N.

4. Conclusion: - Based on the given constraints, the maximum number of odd digits in the decimal representation of a number N is 0. - Therefore, the decimal representation of N does not contain any odd digits.

Please let me know if you need any further clarification or assistance!