Question

экипаж судна заморозил 9 3/18 т рыбы. в первый день заготовили 2/5 всей рыбы, а во второй 4/9 остатка. сколько тонн рыбы заморозил экипаж судна во 2 день?​

Answer 1

Ответ:

Пошаговое объяснение:

Answer 2

To answer the question, let's break it down step by step.

1. The crew of the ship froze 9 3/18 tons of fish. 2. On the first day, they prepared 2/5 of the total fish. 3. On the second day, they prepared 4/9 of the remaining fish.

To find out how many tons of fish the crew froze on the second day, we need to calculate the remaining fish after the first day and then calculate 4/9 of that amount.

Calculation:

1. Total fish frozen: 9 3/18 tons 2. Fish prepared on the first day: 2/5 * 9 3/18 tons 3. Remaining fish after the first day: (1 - 2/5) * 9 3/18 tons 4. Fish prepared on the second day: 4/9 * (1 - 2/5) * 9 3/18 tons

Let's calculate the answer step by step:

1. Total fish frozen: 9 3/18 tons - Answer: 9 3/18 tons

2. Fish prepared on the first day: 2/5 * 9 3/18 tons - To calculate this, we need to convert the mixed number (9 3/18) to an improper fraction: - 9 3/18 = (9 * 18 + 3) / 18 = 171/18 - Fish prepared on the first day: 2/5 * 171/18 tons - Simplifying the fraction: (2 * 171) / (5 * 18) = 342/90 = 19/5 = 3 4/5 - Answer: 3 4/5 tons

3. Remaining fish after the first day: (1 - 2/5) * 9 3/18 tons - To calculate this, we need to subtract the fish prepared on the first day from the total fish frozen: - Remaining fish after the first day: (1 - 2/5) * 9 3/18 tons - Simplifying the fraction: (3/5) * 9 3/18 tons - Remaining fish after the first day: (3/5) * 171/18 tons - Simplifying the fraction: (3 * 171) / (5 * 18) = 513/90 = 57/10 = 5 7/10 - Answer: 5 7/10 tons

4. Fish prepared on the second day: 4/9 * (1 - 2/5) * 9 3/18 tons - To calculate this, we need to multiply the remaining fish after the first day by 4/9: - Fish prepared on the second day: 4/9 * (5 7/10) tons - Converting the mixed number (5 7/10) to an improper fraction: - 5 7/10 = (5 * 10 + 7) / 10 = 57/10 - Fish prepared on the second day: 4/9 * 57/10 tons - Simplifying the fraction: (4 * 57) / (9 * 10) = 228/90 = 38/15 = 2 8/15 - Answer: 2 8/15 tons

Therefore, the crew of the ship froze approximately 2 8/15 tons of fish on the second day.

Answer: The crew of the ship froze approximately 2 8/15 tons of fish on the second day.