
Маса кавуна 10 кг, вода складає 97% від його маси. Після того, як кавун розрізали на скибки та
лишили на сонці, частина води випарувалася. В результаті вміст води в кавуні став складати 96%. Якою стала маса кавуна після випаровування води?

Ответы на вопрос

Ответ:
10кг+97%=107
96%+97=197%
0,97-0,96=0,01
0,01=0,01



Calculation of Water Evaporation from Watermelon
To find the final mass of the watermelon after water evaporation, we can use the information given in the question. Let's break down the problem step by step:
1. The initial mass of the watermelon is 10 kg. 2. The water content in the watermelon is 97% of its mass. 3. After the watermelon is cut into slices and left in the sun, some of the water evaporates. 4. The water content in the watermelon becomes 96% of its mass.
To find the final mass of the watermelon, we need to calculate the mass of water that evaporated.
Calculation:
Let's assume the mass of water that evaporated is "x" kg.
The initial mass of water in the watermelon is 97% of 10 kg, which is 0.97 * 10 kg = 9.7 kg.
After the water evaporates, the water content becomes 96% of the final mass. So, the mass of water remaining in the watermelon is 96% of the final mass, which is 0.96 * (10 kg - x) kg.
According to the given information, the mass of water remaining in the watermelon is equal to the initial mass of water minus the mass of water that evaporated:
0.96 * (10 kg - x) kg = 9.7 kg
Now, let's solve this equation to find the value of "x" (the mass of water that evaporated).
0.96 * (10 kg - x) kg = 9.7 kg
Dividing both sides of the equation by 0.96:
10 kg - x kg = 9.7 kg / 0.96
Simplifying:
10 kg - x kg = 10.104 kg
Subtracting 10 kg from both sides:
- x kg = 10.104 kg - 10 kg
Simplifying:
- x kg = 0.104 kg
Multiplying both sides by -1 to isolate "x":
x kg = -0.104 kg
Since mass cannot be negative, we can conclude that no water evaporated from the watermelon.
Answer:
The mass of the watermelon remained the same after the water evaporation process. It is still 10 kg.


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