Question

Петя шел со скоростью 10 м/с. Коля ехал в автобусе 2.5 раза больше чем Петя. В полпути автобус сломался и Коля шел пешком со скоростью 5м/с. Чему равняется разность времени?

Answer 1

Ответ:

Разность времени Пети и автобуса в 5 раз

Пошаговое объяснение:

1) 10*2,5=25

2)25:5=5

Answer 2

Calculation of Time Difference

To calculate the time difference between Petya and Kolya, we need to consider the distances they traveled and their respective speeds.

Petya walked with a speed of 10 m/s. Let's assume the total distance Petya walked is d.

Kolya traveled in a bus that was 2.5 times faster than Petya's walking speed. Therefore, Kolya's speed in the bus was 2.5 * 10 m/s = 25 m/s.

The bus broke down halfway, so Kolya had to continue on foot with a speed of 5 m/s.

To find the time difference, we need to calculate the time it took for each person to travel their respective distances.

The time it took for Petya to travel the distance d is given by the formula:

Time taken by Petya = Distance / Speed = d / 10 seconds

The time it took for Kolya to travel the distance d is given by the formula:

Time taken by Kolya = (Distance / Speed in the bus) + (Distance / Speed on foot) = d / 25 + d / 5 seconds

To find the time difference, we subtract the time taken by Petya from the time taken by Kolya:

Time difference = (d / 25 + d / 5) - (d / 10) seconds

Simplifying the equation, we get:

Time difference = (2d + 5d - 5d) / 50 seconds

Time difference = 2d / 50 seconds

Therefore, the time difference between Petya and Kolya is 2d / 50 seconds.

Please note that we need the value of the distance d to calculate the exact time difference. Unfortunately, the given information does not provide the value of d.