Question

Ширина прямокутника дорівнює 40 мм. Це становить 4/7 його довжини. Обчисли периметр і площу прямокутника.

Answer 1

Ответ: длина 40:4/7=40*7/4=70 мм. Периметр 2*(70+40)=220 мм. Площадь 70*40=2800 мм^2.

Пошаговое объяснение:

Answer 2

Problem Analysis

We are given that the width of a rectangle is 40 mm, which is equal to 4/7 of its length. We need to calculate the perimeter and area of the rectangle.

Solution

Let's assume the length of the rectangle is L mm.

According to the given information, the width of the rectangle is 40 mm, which is equal to 4/7 of its length. Mathematically, we can represent this as:

40 mm = (4/7) * L mm

To find the value of L, we can solve this equation:

L = (40 mm * 7) / 4

Now that we have the value of L, we can calculate the perimeter and area of the rectangle.

Calculating the Perimeter

The perimeter of a rectangle is given by the formula:

Perimeter = 2 * (Length + Width)

Substituting the values, we get:

Perimeter = 2 * (L + 40 mm)

Calculating the Area

The area of a rectangle is given by the formula:

Area = Length * Width

Substituting the values, we get:

Area = L * 40 mm

Let's calculate the values.

Calculation

Given: Width = 40 mm

Using the equation: 40 mm = (4/7) * L mm

Solving for L: L = (40 mm * 7) / 4

L = 70 mm

Now, let's calculate the perimeter and area.

Perimeter = 2 * (L + 40 mm) Perimeter = 2 * (70 mm + 40 mm) Perimeter = 2 * 110 mm Perimeter = 220 mm

Area = L * 40 mm Area = 70 mm * 40 mm Area = 2800 mm^2

Answer

The perimeter of the rectangle is 220 mm and the area is 2800 mm^2.

Please let me know if you need any further assistance.