Question

Паук сплёл тонкую паутину в форме окружности с центром О, разделил её точками A, B, C, D, E, F, G, H на восемь одинаковых частей и соединил противоположные точки толстыми паутинками AE, BF, CG, DH. известно, что паук проползает:• путь ABCOEFGOA за 1 час;• путь AOBA за 24 минуты.За какое время паук проползёт всю окружность?Скорость движения паука по тонким паутинкам окружности постоянна.Скорость движение паука по толстым паутинкам также постоянно, но отличается от его скорости по тонким паутинкам.ответ дайте в минутах.​

Answer 1

Ответ:

192 мин

Пошаговое объяснение:

Т.к 8 точек скорость постоянна

Answer 2

Problem Analysis

We are given a spider web in the shape of a circle with center O, divided into eight equal parts by points A, B, C, D, E, F, G, and H. The spider connects the opposite points with thick spider silk, forming lines AE, BF, CG, and DH. We are also given the following information: - The spider crawls the path ABCOEFDOA in 1 hour. - The spider crawls the path AOB in 24 minutes.

We need to determine how long it will take for the spider to crawl the entire circumference of the circle.

Solution

To solve this problem, we need to find the time it takes for the spider to crawl along the thick spider silk lines AE, BF, CG, and DH. Then we can add this time to the time it takes for the spider to crawl along the thin spider silk lines AB, BC, CD, DE, EF, FG, GH, and HA.

Let's assume the time it takes for the spider to crawl along the thick spider silk lines is t minutes. Since the spider's speed along the thin spider silk lines is constant, we can use the given information to find the spider's speed along the thick spider silk lines.

From the given information, we know that the spider crawls the path AOB in 24 minutes. Since the spider crawls along the thin spider silk lines AB and BO, which are opposite sides of the circle, the time it takes to crawl along these lines is equal. Therefore, the spider takes 12 minutes to crawl along each of these lines.

Now, let's calculate the time it takes for the spider to crawl along the thick spider silk lines. Since the spider crawls the path ABCOEFDOA in 1 hour, and the time it takes to crawl along the thin spider silk lines AB and BO is 12 minutes each, the remaining time is 1 hour - 2 * 12 minutes = 1 hour - 24 minutes = 36 minutes. This time includes the time it takes for the spider to crawl along the thick spider silk lines AE, BF, CG, and DH.

Since the spider crawls along the thick spider silk lines AE, BF, CG, and DH, which are opposite sides of the circle, the time it takes to crawl along these lines is equal. Therefore, the spider takes 36 minutes / 4 = 9 minutes to crawl along each of these lines.

Now, let's calculate the total time it takes for the spider to crawl the entire circumference of the circle. The circle is divided into 8 equal parts, and the spider crawls along each part in the following order: AB, BC, CD, DE, EF, FG, GH, and HA. Since the spider takes 12 minutes to crawl along each of these lines, the total time it takes for the spider to crawl the entire circumference is 8 * 12 minutes = 96 minutes.

Therefore, the spider will crawl the entire circumference of the circle in 96 minutes.

Answer: The spider will crawl the entire circumference of the circle in 96 minutes.