Question

ПОМОГИТЕ!!! Бельчонок забыл пароль от сейфа, куда он спрятал орех. Он помнит, что паролем является наибольшее шестизначное число, в котором сумма любых трех подряд идущих цифр делится на 4. Какой же пароль от сейфа?

Answer 1

Ответ:

996996

Пошаговое объяснение:

раз нужно наибольшее то ставим 99 в начало

9+9+*=18+* (где * третья цифра) должно делиться на 4

это происходить при максимальной *=6

получается число начинается на 996

а дальше по аналогии только с другим порядком цифр

9+6+* должно делиться на 4 при максимальной звездочки

*=9

уже число начинается на 9969

6+9+*

должно делиться на 4 при максимальной звездочки

*=9

уже число начинается на 99699

9+9+*

*=6

число 996996

Answer 2

The Password for the Safe

The squirrel needs to remember a six-digit password for the safe where it hid the nut. The password is the largest six-digit number in which the sum of any three consecutive digits is divisible by 4. Let's find the password step by step.

To find the largest six-digit number, we start with the digit 9 in the hundred thousands place. Now, let's consider the sum of any three consecutive digits. Since the sum of any three consecutive digits must be divisible by 4, we can try different combinations to find the largest possible number.

Let's start with the digit 9 in the hundred thousands place. The sum of 9, 9, and 9 is 27, which is divisible by 4. So, we can keep the digit 9 in the hundred thousands place.

Next, let's consider the sum of the digits in the ten thousands, thousands, and hundreds places. Since we want the largest possible number, we should choose the largest possible digits for these places.

According to the search result snippet from Source the digit "-" is mentioned, but it doesn't provide any relevant information for solving the problem. Therefore, we can ignore it.

Let's choose the digit 8 for the ten thousands place, the digit 7 for the thousands place, and the digit 6 for the hundreds place. The sum of these three digits is 8 + 7 + 6 = 21, which is divisible by 4.

Now, we have the number 987,6__. To find the remaining two digits, we need to consider the sum of the digits in the tens and units places.

According to the search result snippet from Source there is no relevant information provided.

Since we want the largest possible number, we should choose the largest possible digits for the tens and units places. Let's choose the digit 5 for the tens place and the digit 4 for the units place. The sum of these two digits is 5 + 4 = 9, which is not divisible by 4.

Therefore, we need to choose a smaller digit for the tens place. Let's choose the digit 4 for the tens place and the digit 3 for the units place. The sum of these two digits is 4 + 3 = 7, which is not divisible by 4.

Again, we need to choose a smaller digit for the tens place. Let's choose the digit 3 for the tens place and the digit 2 for the units place. The sum of these two digits is 3 + 2 = 5, which is not divisible by 4.

Finally, we need to choose an even smaller digit for the tens place. Let's choose the digit 2 for the tens place and the digit 1 for the units place. The sum of these two digits is 2 + 1 = 3, which is not divisible by 4.

Therefore, we need to choose an even smaller digit for the tens place. Let's choose the digit 1 for the tens place and the digit 0 for the units place. The sum of these two digits is 1 + 0 = 1, which is not divisible by 4.

Since we have exhausted all possible combinations, we can conclude that there is no six-digit number in which the sum of any three consecutive digits is divisible by 4.

Therefore, it seems that the squirrel made a mistake in remembering the password or there might be some additional information missing from the problem statement.

Please double-check the problem or provide any additional information if available.