Question

вася шел от дома до школы со скоростью в 2 раза меньше чем нужно чтобы успеть. На середине пути Вася спохватился, что опаздывает, и рванул, что есть мочи в школу. Успеет ли Вася к первому уроку?​

Answer 1

Ответ:

Пошаговое объяснение:

Пусть V - скорость с которой он должен был идти чтобы прийти вовремя

t -время ; S расстояние (путь)

Также известно что $\rm t=\dfrac{S}{V}$

По условию сказано что он шел со скоростью V/2 полпути

Но так как он шел V/2 ; и  полпути  

$\rm \dfrac{S}{\dfrac{2}{\dfrac{V}{2} } } =\dfrac{S}{V} =t$  

Это означает что пройдя пол пути он уже истратил все время

Из чего можно сделать вывод что с какой бы он скоростью он не бежал он опоздает на 1-й урок

Answer 2

Problem Analysis

Vasya is walking from home to school at a speed that is 2 times slower than the required speed to arrive on time. However, halfway through the journey, Vasya realizes that he is running late and starts running to school. The question is whether Vasya will make it to the first lesson on time.

Solution

To determine if Vasya will make it to the first lesson on time, we need to compare the time it takes for him to walk half the distance at a slower speed and the time it takes for him to run the remaining half of the distance at a faster speed.

Let's assume: - The total distance from home to school is represented by D. - The required speed to arrive on time is represented by S. - The slower speed at which Vasya walks is represented by V.

The time it takes for Vasya to walk half the distance at the slower speed is given by: T1 = (D/2) / V

The remaining distance from the midpoint to school is also D/2. Since Vasya starts running, we need to determine the speed at which he runs. Since he is running with all his might, we can assume that he is running at a speed that is twice the required speed to arrive on time, which is 2S.

The time it takes for Vasya to run the remaining half of the distance at the faster speed is given by: T2 = (D/2) / (2S)

If the total time it takes for Vasya to walk half the distance and run the remaining half is less than the time required to arrive on time, then Vasya will make it to the first lesson on time.

Let's calculate the time it takes for Vasya to walk and run:

T1 = (D/2) / V

T2 = (D/2) / (2S)

If T1 + T2 is less than or equal to the time required to arrive on time, then Vasya will make it to the first lesson on time.

Calculation

Since we don't have specific values for the distance, required speed, and Vasya's walking speed, we cannot provide a definitive answer. However, we can provide the general steps to calculate it.

1. Determine the total distance from home to school. 2. Determine the required speed to arrive on time. 3. Determine Vasya's walking speed, which is 2 times slower than the required speed. 4. Calculate the time it takes for Vasya to walk half the distance at the slower speed: T1 = (D/2) / V. 5. Calculate the time it takes for Vasya to run the remaining half of the distance at a speed that is twice the required speed: T2 = (D/2) / (2S). 6. Add T1 and T2 to get the total time it takes for Vasya to reach school. 7. Compare the total time with the time required to arrive on time. If the total time is less than or equal to the required time, Vasya will make it to the first lesson on time.

Please provide the specific values for the distance, required speed, and Vasya's walking speed, and we can help you calculate whether Vasya will make it to the first lesson on time.