Question

Взяли три мотка верёвки.от первого отрезали 1/4 от второго - 1/7 от третьего 1/5.какой из мотков стал короче?Ответ обоснуйте. дам 30 баллов

Answer 1

Приведём все дроби к общему знаменателю - 140.

1/4 = 35/140

1/7 = 20/140

1/5 = 28/140.

Answer 2

Ответ:

Пошаговое объяснение:

Приведем все дроби к общему знаменателю - 140

1/4 = 35/140

1/7= 20/140

1/5= 28/140

так как общий знаменатель у всех равный смотрим по числителю

самый короткий второй моток

Answer 3

Problem Analysis

To solve this problem, we need to determine which of the three ropes became shorter after the given operations.

Calculations

Let's calculate the lengths of the ropes after the operations: - From the first rope, 1/4 was cut. - From the second rope, 1/7 was cut. - From the third rope, 1/5 was cut.

Let's assume the original lengths of the ropes are A, B, and C. After the operations, the lengths become: - First rope: A - (1/4)A = (3/4)A - Second rope: B - (1/7)B = (6/7)B - Third rope: C - (1/5)C = (4/5)C

Comparison

Now, we need to compare the new lengths to determine which rope became shorter.

- First rope: (3/4)A - Second rope: (6/7)B - Third rope: (4/5)C

Conclusion

The rope that became shorter is the one with the smallest fraction of its original length remaining after the operations. Therefore, the rope that became shorter is the one for which the fraction remaining is the smallest.

Let's compare the fractions: - (3/4)A - (6/7)B - (4/5)C

The smallest fraction is (3/4), so the first rope became the shortest after the operations.

So, the first rope became shorter after the operations.

I hope this helps! If you have further questions, feel free to ask.