Question

Складіть рiвняння кола, центр якого знаходиться в точцi М(-9,8) i радіусом 15​

Answer 1

Ответ:

(х+9)^2+(у-8)^2=225

Пошаговое объяснение:

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Answer 2

Equation of a Circle

To find the equation of a circle with its center at point M(-9,8) and a radius of 15, we can use the standard form of the equation of a circle:

Equation of a Circle: (x - h)^2 + (y - k)^2 = r^2

Where (h, k) represents the coordinates of the center of the circle, and r represents the radius.

In this case, the center of the circle is at point M(-9,8) and the radius is 15. Plugging these values into the equation, we get:

Equation of the Circle: (x - (-9))^2 + (y - 8)^2 = 15^2

Simplifying further:

Equation of the Circle: (x + 9)^2 + (y - 8)^2 = 225

So, the equation of the circle with its center at point M(-9,8) and a radius of 15 is (x + 9)^2 + (y - 8)^2 = 225.

Please let me know if there's anything else I can help you with!