Question

Собственная скорость катера 20 целых 4/5 км/ч, а скорость течения реки 1 целая 1/2 км/ч. Найдите скорость катера по течению и против течения.

Answer 1

Ответ:

20 4/5 +1 1/2=20 8/10+1 5/10=21 13/10= 22 3/10 км/ч скорость катера по течению 20 4/5-1 1/2 =20 8/10-1 5/10=19 3/10 км/ч скорость катера против течения.

Answer 2

Calculating Boat Speed

To find the speed of the boat in still water and against the current, we can use the following formulas:

Speed of the boat in still water (B) = (Speed of the boat + Speed of the current) Speed of the boat against the current (B - C) = (Speed of the boat - Speed of the current)

Given: - Speed of the boat (B) = 20 4/5 km/h - Speed of the current (C) = 1 1/2 km/h

Calculating Speed of the Boat in Still Water

To find the speed of the boat in still water, we add the speed of the boat to the speed of the current.

B = 20 4/5 + 1 1/2 B = 20.8 + 1.5 B = 22.3 km/h

So, the speed of the boat in still water is 22.3 km/h.

Calculating Speed of the Boat Against the Current

To find the speed of the boat against the current, we subtract the speed of the current from the speed of the boat.

B - C = 20 4/5 - 1 1/2 B - C = 20.8 - 1.5 B - C = 19.3 km/h

So, the speed of the boat against the current is 19.3 km/h.

Therefore, the speed of the boat in still water is 22.3 km/h and the speed of the boat against the current is 19.3 km/h.