Question

Первая труба наполняет резервуар объемом 100 литров на 6 минут больше, чем вторая труба. Сколько 15литров воды в минуту пропускает вторая труба, если она пропускает на литров воды в минуту больше, чем первая?

Answer 1

Ответ:

25

Пошаговое объяснение:

100/x-100/x+15 = 6

100(x+15)-100x = 6x(x+15)

1500=6x^2+90x

2x^2+30x-500=0

x1 = 10

x2=-25 (не может быть отрицательным)

2 труба = 10 + 15

1 труба = 10

Answer 2

Problem Analysis

We are given that the first pipe fills a reservoir with a volume of 100 liters in 6 minutes more than the second pipe. We need to determine the rate at which the second pipe fills the reservoir if it fills it 1 liter per minute more than the first pipe.

Solution

Let's assume that the second pipe fills the reservoir at a rate of x liters per minute. According to the problem, the first pipe fills the reservoir at a rate of x - 1 liter per minute.

We can set up the following equation based on the given information:

100 / (x - 1) = 100 / x + 6

To solve this equation, we can cross-multiply and simplify:

100x = 100(x - 1) + 6(x - 1)

Simplifying further:

100x = 100x - 100 + 6x - 6

Combining like terms:

100x - 100x - 6x = -100 - 6

Simplifying:

-6x = -106

Dividing both sides by -6:

x = 17.67

Therefore, the second pipe fills the reservoir at a rate of approximately 17.67 liters per minute.

Answer

The second pipe fills the reservoir at a rate of approximately 17.67 liters per minute.