Question

15-k=929:b=72:9p+7•6=5130-c=18​

Answer 1

k=15-9=6 k=6

72:9=8 b=??

p+42=51 p=51-42=9 p=9

c=30-18=12 c=12

что во втором не знаю, 29 не делится на 8 без остатка, может там другое число?

Answer 2

The given equation is:

15 - k = 929 : b = 72 : 9p + 7 • 6 = 5130 - c = 18

Let's break it down and solve each part separately:

1. 15 - k = 929: To solve for 'k', we need to isolate it on one side of the equation. Let's subtract 15 from both sides:

   15 - k - 15 = 929 - 15 -k = 914

   To get 'k' by itself, we multiply both sides by -1 (since multiplying by -1 on both sides will reverse the sign):

   -1 * -k = -1 * 914 k = -914

   So, k = -914.

2. b = 72: No further steps are needed. Here, b = 72.

3. 9p + 7 • 6 = 5130: Let's simplify the equation:

   9p + 7 • 6 = 5130 9p + 42 = 5130

   Next, subtract 42 from both sides:

   9p + 42 - 42 = 5130 - 42 9p = 5088

   Finally, divide both sides by 9 to solve for 'p':

   9p / 9 = 5088 / 9 p = 565.33 (rounded to two decimal places)

   So, p ≈ 565.33.

4. 5130 - c = 18: To solve for 'c', we need to isolate it on one side of the equation. Let's subtract 5130 from both sides:

   5130 - c - 5130 = 18 - 5130 -c = -5112

   Multiplying both sides by -1:

   -1 * -c = -1 * -5112 c = 5112

   So, c = 5112.

To summarize the solutions: k = -914, b = 72, p ≈ 565.33, c = 5112.