Question

2. Выполни чертёж к задаче. Реши задачу. В бассейне плывут в одном направлении два мальчика. Первый плывет со скоростью 100 см/с и находится впереди второго на 400 см. Второй плывет со скоростью 150 см/с. Через какое время второй мальчик догонит первого? Помогите пожалуйста

Answer 1

Ответ:

8 секунд

Пошаговое объяснение:

1) 150 - 100 = 50 (см/c) это скорость сближения

2) 400 : 50 = 8 (с) Через какое время второй мальчик догонит первого

Надеюсь помог

Answer 2

Problem Analysis

We are given two boys swimming in a pool in the same direction. The first boy is swimming at a speed of 100 cm/s and is ahead of the second boy by 400 cm. The second boy is swimming at a speed of 150 cm/s. We need to determine how long it will take for the second boy to catch up to the first boy.

Solution

To solve this problem, we can set up an equation based on the relative speeds of the two boys. Let's assume that the second boy catches up to the first boy after time 't' seconds.

The distance covered by the first boy in 't' seconds is given by: Distance1 = Speed1 * t

The distance covered by the second boy in 't' seconds is given by: Distance2 = Speed2 * t

Since the second boy catches up to the first boy, the distances covered by both boys must be equal. Therefore, we can set up the following equation:

Distance1 = Distance2

Substituting the values we have: Speed1 * t = Speed2 * t + 400

Simplifying the equation: 100t = 150t + 400

Now, we can solve for 't' to find the time it takes for the second boy to catch up to the first boy.

Calculation

Let's solve the equation to find the value of 't':

100t = 150t + 400

Subtracting 150t from both sides: -50t = 400

Dividing both sides by -50: t = -400 / -50 = 8

Therefore, it will take the second boy 8 seconds to catch up to the first boy.

Answer

The second boy will catch up to the first boy after 8 seconds.

Note: The solution assumes that the boys are swimming in a straight line and that their speeds remain constant throughout the time period.