Question

А)3|х|+5=11 в)9|х|=-16

Answer 1

Ответ:

3|x|=11-5

3|x|=6

x= 6:3

x = 2

а если число в модуле, то икс может принять 2 значения. 2 и -2

9|х|=-16

х=-16:9

получается -16/9

и переводим 1 1/7 или -1 1/7

Answer 2

Ответ:

а) х¹= -2; х²= 2 в)

Пошаговое объяснение:

если что в) на фото

Answer 3

А) To solve the equation 3|x| + 5 = 11, we'll isolate the absolute value term and solve for x. Here's how:

Subtract 5 from both sides: 3|x| = 11 - 5 3|x| = 6

Divide both sides by 3: |x| = 6/3 |x| = 2

Since the absolute value of a number is always non-negative, we have two cases to consider:

Case 1: x is positive If x is positive, then |x| = x. Substituting this into the equation: x = 2

Case 2: x is negative If x is negative, then |x| = -x. Substituting this into the equation: -x = 2

Multiply both sides by -1: x = -2

So the equation 3|x| + 5 = 11 has two solutions: x = 2 and x = -2.

в) To solve the equation 9|x| = -16, we'll notice that the absolute value of any number is always non-negative. Therefore, it is impossible for the absolute value of a number to be equal to a negative number. Hence, the equation 9|x| = -16 has no solutions.