Question

804. Первый мастер может выполнить задание за 4, второй -за 5 ч. Третий мастер может выполнить за 1 ч на 0,1 задания больше, чем второй. Какая часть задания останется невыполнеой, если три мастера будут работать совместно ровно 1ч? Ответ:0,25 только нужно решениепожалуйста!​

Answer 1

1/4+1/5+(1,5)15=0,25+0,2+0,3=0,75

1-0,75=0,25

Ответ:0,25части задания

Answer 2

Problem Analysis

We are given three masters who can complete a task in different amounts of time. The first master can complete the task in 4 hours, the second master can complete it in 5 hours, and the third master can complete it in 1 hour. The third master can complete 0.1 more of the task than the second master. We need to determine the fraction of the task that remains incomplete if all three masters work together for exactly 1 hour.

Solution

To solve this problem, we can calculate the fraction of the task completed by each master in 1 hour and then sum them up to find the total fraction of the task completed in 1 hour. Finally, we subtract this total fraction from 1 to find the fraction of the task that remains incomplete.

Let's calculate the fraction of the task completed by each master in 1 hour:

- The first master can complete the task in 4 hours, so in 1 hour, they can complete 1/4 of the task. - The second master can complete the task in 5 hours, so in 1 hour, they can complete 1/5 of the task. - The third master can complete 0.1 more of the task than the second master, so in 1 hour, they can complete 1/5 + 0.1 = 0.3 of the task.

Now, let's sum up the fractions of the task completed by each master in 1 hour:

1/4 + 1/5 + 0.3 = 0.55

Therefore, if all three masters work together for 1 hour, they can complete 0.55 of the task. To find the fraction of the task that remains incomplete, we subtract this value from 1:

1 - 0.55 = 0.45

So, 0.45 or 45% of the task remains incomplete after 1 hour of work by all three masters.

Answer

If three masters work together for exactly 1 hour, 0.45 or 45% of the task will remain incomplete.

Note: The sources provided do not contain relevant information for this specific problem.