Question

Из двух домов одновременно навстречу друг другу выбежали кошка, которая бежала со скоростью 4 м/с, и кот, который двигался в 2 раза быстрее, чем кошка. Встреча произошла через 20 с. Каково расстояние между домами?

Answer 1

Ответ:

расстояние между домами 240м

Пошаговое объяснение:

1)4*2=8 м/c  скорость кота

2)4+8=12 м/c   скорость сближения кота и кошки

S=vt   формула для нахождения расстояния

3)12*20=240 м расстояние между домами

Answer 2

1) 4*20 = 80м
2) 4*2*20 = 160м
3) 80+160 = 240м
Ответ:240м

Answer 3

Problem Analysis

We are given that a cat and a cat ran towards each other from two different houses. The cat runs at a speed of 4 m/s, while the cat runs at a speed that is twice as fast as the cat. They meet after 20 seconds. We need to find the distance between the houses.

Solution

Let's assume the distance between the two houses is d.

The cat runs at a speed of 4 m/s, so in 20 seconds, it covers a distance of 4 m/s * 20 s = 80 meters.

The cat runs at a speed that is twice as fast as the cat, so its speed is 2 * 4 m/s = 8 m/s. In 20 seconds, the cat covers a distance of 8 m/s * 20 s = 160 meters.

Since the cat and the cat are running towards each other, the total distance they cover is equal to the distance between the houses.

Therefore, the distance between the houses (d) is the sum of the distances covered by the cat and the cat: d = 80 meters + 160 meters = 240 meters.

Answer

The distance between the two houses is 240 meters.