Question

Log (5x-5) 5 log (x-1)^2 125 2

Answer 1

5х-5+5х-5^212>2=5х+5
Короче ровно 124<^35

Answer 2

To clarify, I assume you want me to evaluate the expression:

log(5x-5) * 5 * log((x-1)^2, 125^2)

Let's break it down step by step:

1. Simplify the logarithmic expressions:

   log(5x-5) can be rewritten as log(5(x-1)) since 5x - 5 can be factored out to 5(x-1).

   log((x-1)^2, 125^2) can be rewritten as log((x-1)^2, 5^6) since 125^2 equals 5^6.

2. Apply the logarithmic property: log(a^m, b^n) = m * log(a, b)

   Applying the property to the expression, we have:

   log(5(x-1)) * 5 * 2 * log(x-1, 5^3)

   Simplifying further:

   10 * log(5(x-1)) * log(x-1, 5^3)

3. Evaluate the logarithmic expressions:

   log(5(x-1)) is the logarithm of (x-1) to the base 5.

   log(x-1, 5^3) is the logarithm of 5^3 to the base (x-1).

4. Substitute the values:

   Since we don't have specific values for x, we can't simplify the expression any further. Therefore, the expression remains as:

   10 * log(5(x-1)) * log(x-1, 5^3)

Please note that if you have specific values for x, you can substitute them into the expression and evaluate it further.