Question

Розв'яжіть рівняння : а) lxl-2=-3; б)lx-4l=0​

Answer 1

Ответ:

lxl-2=-3

|х|= -3+2

|х| = -1

корней нет, любое число по модулю ≥0

_______________

|х-4|=0 → х-4=0 → х=4

Answer 2

I can help you solve these equations. Here are the steps:

а) lxl-2=-3

To solve this equation, we need to consider two cases: x >= 0 and x < 0.

If x >= 0, then lxl = x and the equation becomes x - 2 = -3. Solving for x, we get x = -1. However, this solution does not satisfy the condition x >= 0, so we reject it.

If x < 0, then lxl = -x and the equation becomes -x - 2 = -3. Solving for x, we get x = 1. This solution satisfies the condition x < 0, so we accept it.

Therefore, the only solution for this equation is x = 1.

б) lx-4l=0

To solve this equation, we need to find the value of x that makes the expression inside the absolute value equal to zero. That is, we need to solve x - 4 = 0. The solution is x = 4.

Therefore, the only solution for this equation is x = 4.

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