Question

Сколько граммов воды надо добавить к 50 г раствора содержащего 8% соли чтобы получить 5% раствор?​

Answer 1

Ответ:

Было 50г -8% Стало 50+хг-5% 50*0,08=(50+x)*0,05 4=2,5+0,05ч 0,05х=1,5 х=1,5:0,05 х=30г воды добавили

Answer 2

Calculating the Amount of Water Needed to Create a 5% Solution from an 8% Solution

To calculate the amount of water needed to add to a 50g solution containing 8% salt to obtain a 5% solution, we can use the following formula:

Initial amount of salt / (Initial amount of salt + added water) = Desired concentration of salt

Let's calculate the amount of water needed using this formula.

Given: - Initial amount of salt = 8% of 50g = 0.08 * 50g = 4g - Desired concentration of salt = 5% - Let's assume the amount of water to be added is x grams.

Using the formula: 4g / (50g + x) = 5%

Solving for x: 4g = 5% * (50g + x) 4g = 0.05 * (50g + x) 4g = 2.5g + 0.05x 0.05x = 4g - 2.5g 0.05x = 1.5g x = 1.5g / 0.05 x = 30g

Therefore, 30 grams of water need to be added to the 50g solution containing 8% salt to obtain a 5% solution.