Question

3х²+7х-20формат х1=х2=​

Answer 1

Ответ:

решение смотри на фотографии

Answer 2

Пошаговое объяснение:

3х² + 7х - 20

3х² + 7х - 20 = 0

а = 3; в = 7; с = -20

Д = в² + 4ас

Д = 7² + 4 * 3 * (-20) = 49 + 240 = 289

Д > 0, значит уравнение имеет 2 корня

√Д = √289 = 17

х1 = (-в - √Д)/2а

х1 = (-7 - 17)/2*3 = -24/6 = -4

х2 = (-в + √Д)/2а

х2 = (-7 + 17)/2*3 = 10/6 = 5/3 = 1. 2/3

Ответ: -4; 1. 2/3

Answer 3

To find the solutions for the quadratic equation 3x² + 7x - 20 = 0, we can use the quadratic formula. The quadratic formula states that for an equation in the form ax² + bx + c = 0, the solutions are given by:

x = (-b ± √(b² - 4ac)) / (2a)

In our equation, a = 3, b = 7, and c = -20. Substituting these values into the quadratic formula, we have:

x = (-7 ± √(7² - 4 * 3 * -20)) / (2 * 3)

x = (-7 ± √(49 + 240)) / 6

x = (-7 ± √289) / 6

x = (-7 ± 17) / 6

This gives us two possible solutions:

x1 = (-7 + 17) / 6 = 10 / 6 = 5/3

x2 = (-7 - 17) / 6 = -24 / 6 = -4

Therefore, the solutions for the quadratic equation 3x² + 7x - 20 = 0 are x1 = 5/3 and x2 = -4.