Question

(x-2)(x+1)≤0 =======================

Answer 1

Ответ:вот

Пошаговое объяснение:

Answer 2

To solve the inequality (x - 2)(x + 1) ≤ 0, we can use the method of sign chart or interval notation.

Method 1: Sign Chart

1. Find the critical points by setting each factor equal to zero: x - 2 = 0 => x = 2 x + 1 = 0 => x = -1

2. Choose test points in each interval and determine the sign of the expression (x - 2)(x + 1): Test x = -2: (-2 - 2)(-2 + 1) = (-4)(-1) = 4 (positive) Test x = 0: (0 - 2)(0 + 1) = (-2)(1) = -2 (negative) Test x = 3: (3 - 2)(3 + 1) = (1)(4) = 4 (positive)

3. Create a sign chart with the critical points and test points:

   luaCopy code
    -∞    -1    2    +∞
    -------------------------
    +     -     +     +
   

4. Identify the intervals where the expression (x - 2)(x + 1) is less than or equal to zero. From the sign chart, we can see that it's negative or zero when x is between -1 and 2 (inclusive).

Therefore, the solution to the inequality (x - 2)(x + 1) ≤ 0 is -1 ≤ x ≤ 2.

Method 2: Interval Notation

Using the critical points, we can express the solution in interval notation. The intervals where the expression (x - 2)(x + 1) is less than or equal to zero are [-1, 2].

Therefore, the solution to the inequality (x - 2)(x + 1) ≤ 0 is [-1, 2].