Question

5x+y=-7 (x+4) (y-5)=-4​

Answer 1

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Answer 2

To solve the system of equations:

1. 5x + y = -7
2. (x + 4)(y - 5) = -4

We can use the method of substitution.

Let's start by solving equation 1) for y:

5x + y = -7 y = -7 - 5x

Now, substitute this value of y into equation 2):

(x + 4)(-7 - 5x - 5) = -4

Simplify the equation:

(x + 4)(-5x - 12) = -4 -5x^2 - 12x - 5x - 20 = -4 -5x^2 - 17x - 20 + 4 = 0 -5x^2 - 17x - 16 = 0

To solve this quadratic equation, we can use the quadratic formula:

x = (-b ± √(b^2 - 4ac)) / (2a)

For the given equation, a = -5, b = -17, and c = -16. Substituting these values into the quadratic formula:

x = (-(-17) ± √((-17)^2 - 4(-5)(-16))) / (2(-5)) x = (17 ± √(289 - 320)) / (-10) x = (17 ± √(-31)) / (-10)

Since we have a negative value under the square root, the solutions for x will be complex numbers. Therefore, there are no real solutions to this system of equations.