Question

Log 1/7(4x + 1) = -2​

Answer 1

Ответ:

Пошаговое объяснение:

Answer 2

To solve the logarithmic equation log base 1/7(4x + 1) = -2, we can rewrite it in exponential form. In general, if log base b of a is equal to c, then it can be written as b^c = a.

In this case, we have: 1/7^(log base 1/7(4x + 1)) = 1/7^(-2)

Simplifying the right side: 1/7^(log base 1/7(4x + 1)) = 1/(1/49)

Now, we can rewrite the left side using the exponential form: (4x + 1) = 49

Solving for x: 4x + 1 = 49 4x = 49 - 1 4x = 48 x = 48/4 x = 12

Therefore, the solution to the equation log base 1/7(4x + 1) = -2 is x = 12.