Question

F(x)=2sin(cos(3x-π)) при x=5

Answer 1

Це відповідь! Якісь питаня будуть пиши

Answer 2

To evaluate the function f(x) = 2sin(cos(3x-π)) at x = 5, we need to substitute the value of x into the function and calculate the result.

Let's break it down step by step:

1. Substitute x = 5 into the function: f(5) = 2sin(cos(3(5) - π))

2. Simplify the expression inside the cosine function: 3(5) - π = 15 - π

3. Substitute the simplified expression back into the function: f(5) = 2sin(cos(15 - π))

4. Evaluate the cosine of (15 - π): cos(15 - π) ≈ -0.309

5. Substitute the cosine result back into the function: f(5) = 2sin(-0.309)

6. Evaluate the sine of -0.309: sin(-0.309) ≈ -0.303

Therefore, when x = 5, the value of the function f(x) = 2sin(cos(3x-π)) is approximately -0.303.